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BFE.devAI解答 - TypeScript 类型谜题
62. implement Unique<T extends any[]>
type Unique<T extends Array<any>> = T extends [infer U, ...infer R] ? U extends any ? [U, ...Unique<Exclude<R, U>>] : Unique<Exclude<R, U>> : [];type A = Unique<['A', 'A', 'A', 'B', 'B', 'C']>;// A is resolved to ['A', 'A', 'A'] and R is resolved to ['B', 'B', 'C']// Unique<Exclude<R, 'A'>> becomes Unique<['B', 'B', 'C']> = ['B', 'C']// Resulting in ['A', ...['B', 'C']] = ['A', 'B', 'C']// Final output is ['A', 'B', 'C']
In the implementation of Unique
, we use conditional types and recursion to remove duplicate elements from the input array. We extract the first element U
from the array T
, then recursively call Unique
on the remaining elements R
after excluding all occurrences of U
. This process is repeated until all duplicate elements are removed, resulting in the deduplicated array.