<pre class="shiki github-dark shaku"><code>function LazyMan(name, logFn) { // eats, sleeps, sleepFirst const queue = [() =&gt; logFn(`Hi, I'm ${name}.`)]; const executor = { eat: function (item) { queue.push(() =&gt; logFn(`Eat ${item}.`)); return this; }, sleep: function (delay) { queue.push(() =&gt; new Promise(resolve =&gt; setTimeout(() =&gt; resolve(logFn(`Wake up after ${delay} second${delay &gt; 1 ? 's' : ''}.`)), delay * 1000))); return this; }, sleepFirst: function (delay) { queue.unshift(() =&gt; new Promise(resolve =&gt; setTimeout(() =&gt; resolve(logFn(`Wake up after ${delay} second${delay &gt; 1 ? 's' : ''}.`)), delay * 1000))); return this; } }; // All Chaining Methods are synchronous // we are pushing all chain methods return values in to queue Array // All Chain methods are in queue Array, After that we are calling below code // Since setTimeout is Async, when we call this all our methods will be in Queue Array setTimeout(async() =&gt; { for (task of queue) { await task(); } }, 0); return executor;}// LazyMan('Jack', console.log)// .eat('banana')// // .sleep(1)// // .sleepFirst(5)// // .eat('apple')</code></pre>

Simple Approach with Deferr

LazyMan is very lazy, he only eats and sleeps. LazyMan(name: string, logFn: (log: string) => void) would output a message, the passed logFn is used. L…