<pre class="shiki github-dark shaku"><code>/** * @param {string} v1 * @param {string} v2 * @returns 0 | 1 | -1 */function compare(v1, v2) { let len1 = v1.length; let len2 = v2.length; let pt1 = 0, pt2 = 0, num1 = 0, num2 = 0; while(pt1 &lt; len1 || pt2 &lt; len2) { while(pt1 &lt; len1 &amp;&amp; v1[pt1] !== '.') { num1 = num1 * 10 + (v1[pt1] - '0'); pt1++; } while(pt2 &lt; len2 &amp;&amp; v2[pt2] !== '.') { num2 = num2 * 10 + (v2[pt2] - '0'); pt2++; } if (num1 &gt; num2) { return 1; } if (num1 &lt; num2) { return -1; } num1 = 0, num2 = 0; pt1++; pt2++; } return 0;}compare('12.1.0', '12.0.9')compare('12.1.0', '12.1.2')</code></pre>

Two pointer solution with one pass. You don't need to split the v1 & v2. (Interview approved)

Please implement a function to compare 2 semver strings. compare('12.1.0', '12.0.9')// 1, meaning first one is greatercompare('12.1.0', '12.1.2')// -1…