<pre class="shiki github-dark shaku"><code>function findSingle(num) { for (let i = 0; i &lt; num.length; i++) { let count = 0; for (let j = 0; j &lt; num.length; j++) { if (i !== j &amp;&amp; num[i] === num[j]) { count++; } } if (count === 0) { return num[i]; } }}const arr = [10, 2, 2, 1, 0, 0, 10];console.log(findSingle(arr));</code></pre>

Given an array of integers, all integers appear twice except one integer, could you quickly target it ? const arr = [10, 2, 2 , 1, 0, 0, 10]findSingle…