<pre class="shiki github-dark shaku"><code>function uncompress(str) { let stack = []; let currentStr = ''; let currentNum = 0; for (let i = 0; i &lt; str.length; i++) { let c = str.charAt(i); if (isDigit(c)) { currentNum = currentNum * 10 + parseInt(c); } else if (c === '(') { stack.push(currentStr); stack.push(currentNum); currentStr = ''; currentNum = 0; } else if (c === ')') { let k = stack.pop(); let prevStr = stack.pop(); currentStr = prevStr + currentStr.repeat(k); } else { currentStr += c; } } return currentStr;}function isDigit(c) { return c &gt;= '0' &amp;&amp; c &lt;= '9';}</code></pre>

This is my Solution !

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Given a compressed string, return its original form. For example. uncompress('3(ab)') // 'ababab'uncompress('3(ab2(c))') // 'abccabccabcc' 1. a number…