<pre><code class="language-javascript">
/**
 * @param {any} target
 * @param {any[]} sources
 * @return {object}
 */
function objectAssign(target, ...sources) {
  if(!target) throw new Error();
  if(typeof target === 'string') return new String(target);
  if(typeof target === 'number') return new Number(target);
  if(typeof target === 'boolean') return new Boolean(target);

  for(const source of sources) {
    if(!source) continue;

    for(const key in source) {
      if(!source[key]) continue;
      if(source.hasOwnProperty(key)) {
        const objDesc = Object.getOwnPropertyDescriptor(target, key);
       if (objDesc &amp;&amp; des.writable == false) throw new Error();
        target[key] = source[key];
      }
    }

  for(const key of Object.getOwnPropertySymbols(source)) {
      if(!source[key]) continue;
      if(source.hasOwnProperty(key)) {
        target[key] = source[key];
      }
  }


  }
  return target;

}
</code></pre>


This is my accepted solution

The Object.assign() method copies all enumerable own properties from one or more source objects to a target object. It returns the target object. (sou…

27. implement completeAssign() 

27. completeAssign() を実装する

27. 实现completeAssign() 

25. Reorder array with new indexes

25. 配列の順序を変える

25. 更新数组的顺序

26. implement Object.assign()

26. Object.assign()を実装する

26. 实现Object.assign()