<pre class="shiki github-dark shaku"><code>function compress(str) { let compressed = ''; let count = 1; for(let i = 0; i &lt; str.length; i++) { if(str[i] === str[i + 1]) { count++; } else { compressed += str[i]; if(count &gt; 1) { compressed += count; count = 1; } } } return compressed;}</code></pre>

This is my Solution !

Given a string, compress the repeating letters with count number compress('a') // 'a'compress('aa') // 'a2'compress('aaa') // 'a3'compress('aaab') // …