# 109. implement `Math.pow()`

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easy - accepted / - tried

Can you write your own Math.pow() ? The power would only be integers.

`pow(1, 2)// 1pow(2, 10)// 1024pow(4, -1)// 0.25`

All inputs are safe.

**Follow-up**

You can easily solve this problem by multiplying the base one after another, but it is slow.
For power of `n`

, it is needed to do the multiplication `n`

times, can you think of a faster solution ?

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implement it by yourself