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AI solution for JavaScript Coding Question on BFE.dev
18. Improve a function
- This function takes in an array of objects
items
, and an array of key-value pairsexcludes
. It then filters out any objects initems
that have any of the key-value pairs inexcludes
. - No, this function is not working as expected. The filter condition in the forEach loop is incorrect, as it's comparing the value of
pair.k
to the value ofpair.v
instead of comparing the value ofitem[pair.k]
topair.v
. Additionally, the function is using===
instead of!==
which means it's excluding items that match the exclude criteria instead of excluding items that don't match. - The time complexity of this function is O(n*m), where n is the length of
items
and m is the length ofexcludes
. For each exclude criteria, the function filters through all items to check if they have the excluded key-value pair. - One way to optimize the function is to use
Array.reduce
instead ofArray.filter
andArray.forEach
. This way, we can avoid filter chaining and multiple iterations through the items array. We can also useArray.some
to check the excludes array for each item, and break out of the loop early if any exclude criteria matches. Here's an optimized version of the function:
function excludeItems(items, excludes) { return items.reduce((acc, item) => { if (!excludes.some(({ k, v }) => item[k] === v)) { acc.push(item); } return acc; }, []);}
This function uses a single iteration through the items
array, and checks each item against all exclude criteria using Array.some
. It then pushes the item into the accumulator array acc
only if none of the exclude criteria match. The time complexity of this new function is O(n*m), which is the best we can do given that we need to check each item against each exclude criteria.