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AI solution for JavaScript Quiz on BFE.dev
98. Promise executor IV
The code will output 2
by console.log
.
Explanation:
- A new Promise is created with a callback that takes
resolve
andreject
as parameters. - Inside the callback, a new Promise called
promise2
is created by callingPromise.reject('error')
. This means thatpromise2
is immediately rejected with the value'error'
. promise2
has a.then()
method attached to it. This method takes two callbacks: the first one (() => console.log(1)
) will be called ifpromise2
is resolved, and the second one (() => console.log(2)
) will be called ifpromise2
is rejected. In this case, the second callback will be called becausepromise2
is rejected.- Finally,
resolve(promise2)
is called, which means that the outer Promise is resolved with the rejectedpromise2
as its value. promise.then(console.log)
is then called, which means that the function passed to the.then()
method will receive the value of the resolved Promise as its argument. In this case, the value is the rejectedpromise2
, so the inner callback (() => console.log(2)
) will be called and output2
.