AI solution for JavaScript Quiz on BFE.dev
42. Hoisting V

The code will output:

2
3

Explanation:

• The first immediately invoked function expression (IIFE) defines a function called fn inside its block using function declaration syntax, and then calls fn(), which outputs 2.
• Next, the global function declaration fn() is defined, but since the block-scoped fn from the previous IIFE is already defined, this declaration has no effect on the output.
• The second IIFE defines a function called fn1 inside its block using function declaration syntax, and then calls fn1(), which outputs 3.
• The third IIFE defines a function called fn3 inside its block using function declaration syntax, but since the if condition is false, fn3() is never called and there is no output.