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AI solution for JavaScript Quiz on BFE.dev
88. try...catch
The code will output:
a1
b1
c1
Explanation:
- In the first try-catch block, because the catch block doesn't have an argument specified, the catch block will catch the error but not assign it to anything, so the global variable
a
will be assigned the value'a1'
. - In the second try-catch block, the catch block has an argument specified as
b
, so the catch block will catch the error and assign it to a local variableb
, which will shadow the global variableb
. Then the local variableb
will be assigned the value'b1'
. - In the third try-catch block, the catch block has an argument specified as
error
, so the catch block will catch the error and assign it to a local variableerror
, which will not affect the global variablec
. Then the global variablec
will be assigned the value'c1'
.