AI solution for TypeScript puzzle on BFE.dev
46. implement Subtract<A, B>

type Subtract<A extends number, B extends number> = 
  A extends B ? 0 :
  B extends 0 ? A :
  Subtract<A-1, B-1>;

Explanation:

• The Subtract type takes two arguments, A and B, both of which extend number.
• We start by writing a conditional statement to handle the base case when A is equal to B, in which case the result will always be 0.
• Next, we handle the case when B is 0. In this case, the result will always be A.
• Finally, we recursively subtract both A and B by 1 until we reach one of the two base cases.