AI solution for TypeScript puzzle on BFE.dev
6. implement Omit<T, K>

Here's one possible solution using mapped types and the keyof operator:

type MyOmit<T, K extends keyof T> = {
  [P in Exclude<keyof T, K>]: T[P]
}

Explanation:

• We use the mapped type syntax ({ [P in Keys]: Type }) to create a new type with the same keys as T but with a subset of the original properties.
• The Exclude<T, U> utility type is used to exclude the keys in K from the original key set (which is keyof T).
• The result is a type with all the properties from T except for the ones listed in K.

Let's test it with the sample types:

type Foo = {
  a: string
  b: number
  c: boolean
}

type A = MyOmit<Foo, 'a' | 'b'> // { c: boolean }
type B = MyOmit<Foo, 'c'> // { a: string; b: number; }
type C = MyOmit<Foo, 'c' | 'd'> // { a: string; b: number; }

As expected, we get the desired results.