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AI solution for TypeScript puzzle on BFE.dev
50. implement Sort<T>

Here is one possible solution:

type LargerThan<A, B> = A extends B ? false : (B extends A ? false : A);
type SmallerThan<A, B> = B extends A ? LargerThan<A, B> : false;

type Sort<T extends number[]> = T extends []
  ? []
  : T extends [infer X, ...infer Rest]
  ? [
      ...Sort<Extract<SmallerThan<X, Rest[number]>, true>>[],
      X,
      ...Sort<Extract<LargerThan<X, Rest[number]>, true>>[]
    ]
  : T;

First, we define the LargerThan and SmallerThan types as in the previous questions. Then, we define Sort as a generic type that takes an array of numbers (T extends number[]).

The base case is when the array is empty (T extends []), in which case we return an empty array ([]).

In the recursive case, we destructure the array into its first element (X) and the rest of the elements (Rest). We then use the Extract utility type to filter out any false elements from the comparison types (i.e. any values that are neither larger than nor smaller than X). We recursively sort the array of elements smaller than X, concatenate X with the sorted array, and then concatenate the sorted array of elements larger than X.

With this implementation, we should be able to sort any array of non-negative integers in ascending order. Note that this implementation uses recursion and type inference, so it may not be as efficient or performant as other sorting algorithms.