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AI solution for JavaScript Coding Question on BFE.dev
174. CSS Grid Layout auto-placement algorithm - sparse
Here's one possible solution to the problem:
type Grid = Array<Array<number>>type Item = { id: number, style?: { gridRowStart?: number | string, gridRowEnd?: number | string, gridColumnStart?: number | string gridColumnEnd?: number | string }}function layout(rows: number, columns: number, items: Array<Item>): Grid { const grid: Grid = Array.from({ length: rows }, () => Array.from({ length: columns }, () => 0)) let row = 1 let col = 1 for (const item of items) { if (item.style?.gridRowStart && typeof item.style.gridRowStart === 'number') { row = item.style.gridRowStart } if (item.style?.gridColumnStart && typeof item.style.gridColumnStart === 'number') { col = item.style.gridColumnStart } const width = item.style?.gridColumnEnd ? getSpan(item.style.gridColumnEnd) - col + 1 : 1 const height = item.style?.gridRowEnd ? getSpan(item.style.gridRowEnd) - row + 1 : 1 for (let r = row; r < row + height; r++) { for (let c = col; c < col + width; c++) { grid[r-1][c-1] = item.id } } col += width if (col > columns) { col = 1 row++ } } return grid}function getSpan(span: string): number { const parts = span.split(' ') if (parts.length !== 2 || parts[1] !== 'span') { throw new Error(`Invalid grid span value: ${span}`) } const value = parseInt(parts[0], 10) if (isNaN(value)) { throw new Error(`Invalid grid span value: ${span}`) } return value}
Here's how it works:
- The
layout
function initializes an empty grid of the specified size and iterates through the list of items to place them in the grid. - For each item, it extracts the
gridRowStart
,gridRowEnd
,gridColumnStart
, andgridColumnEnd
values from itsstyle
field (if present), and uses them to compute the item's position and size in the grid. - The item is then added to the grid by setting the corresponding cells to its id value.
- Finally, the function returns the completed grid.
Note that the function assumes that all items have valid, non-overlapping positions within the grid. If this is not the case, the results may be incorrect.