83. create an interval

JavaScriptByteDance
Is this helpful ?

medium  - accepted / - tried

You are asked to create a new mySetInterval(a, b) which has a different behavior from window.setInterval, the time between calls is a linear function, growing larger and larger period = a + b * count.

let prev = Date.now()
const func = () => {
  const now = Date.now()
  console.log('roughly ', Date.now() - prev)
  prev = now
}

const id = mySetInterval(func, 100, 200)

// roughly 100, 100 + 200 * 0
// roughly 400,  100 + 200 * 1
// roughly 900,  100 + 200 * 2
// roughly 1600,  100 + 200 * 3
// ....

myClearInterval(id) // stop the interval
  1. Interface is mySetInterval(delay, period), the first delay is used for the first call, and then period is used.
  1. because window.setTimeout and window.setInterval are not accurate in browser environment, they are replaced to other implementation when judging your code. They still have the same interface, and internally keep track of the timing for testing purpose.

Something like below will be used to do the test. (You don't need to read following code to accomplish this task)

let currentTime = 0

const run = (delay, period, clearAt) => {
  currentTime = 0
  pipeline.length = 0
  
  const logs = []

  const func = () => {
    logs.push(currentTime)
  }

  mySetInterval(func, delay, period)
  if (clearAt !== undefined) {
    setTimeout(() => {
      myClearInterval(id)
    }, clearAt)
  }

  while (pipeline.length > 0 && calls.length < 5) {
    const [time, callback] = pipeline.shift()
    currentTime = time
    callback()
  }

  return calls
}

expect(run(100, 200)).toEqual([100,400,900,1600,2500])
expect(run(100, 200, 450)).toEqual([100,400])
expect(run(100, 200, 50)).toEqual([])

Let's try to solve this problem within 10 minutes.

Discuss(20)